Answer :
The tank is in the form of cylinder
its radius is 24 cm and it height till
volume of water intially
[tex]V= \pi r^2h=1357.168 cm^3[/tex]
now four sphere of radius r' are added
so the final height is 18+7=25cm
Volume of water Finally
[tex]V'= \pi r^2h= \pi (24)^2(25)=1884.96 cm^3[/tex]
So the difference between the final and intial values will give the volume of spheres
[tex]4V_{sphere}=V'-V=527.79 cm^3[/tex]
[tex]V_{sphere}=131.95 cm^3[/tex]
[tex] \frac{4}{3} \pi r^3_{sphere}=131.95 [/tex]
[tex]r_{sphere}=5.612486 cm[/tex]
its radius is 24 cm and it height till
volume of water intially
[tex]V= \pi r^2h=1357.168 cm^3[/tex]
now four sphere of radius r' are added
so the final height is 18+7=25cm
Volume of water Finally
[tex]V'= \pi r^2h= \pi (24)^2(25)=1884.96 cm^3[/tex]
So the difference between the final and intial values will give the volume of spheres
[tex]4V_{sphere}=V'-V=527.79 cm^3[/tex]
[tex]V_{sphere}=131.95 cm^3[/tex]
[tex] \frac{4}{3} \pi r^3_{sphere}=131.95 [/tex]
[tex]r_{sphere}=5.612486 cm[/tex]