Answer :
Let x m be the length of the train and y m/s be the speed of the train
then x/y = 8
⇒x = 8y
Also x+264/20 = y
x+264 = 20y
8y+264 = 20y
12y = 264
y = 22
Hence speed of train = 22m/s = 22*18/5 km/hr = 79.2 km/hr
Let x m be the length of the train and y m/s be the speed of the train
then x/y = 8
⇒x = 8y
Also x+264/20 = y
x+264 = 20y
8y+264 = 20y
12y = 264
y = 22
Hence speed of train = 22m/s = 22*18/5 km/hr = 79.2 km/hr