Answer :
√4/9 =2/3
let,
2/3 = a
√2 = b
rational number between a and b = (a+b)/2
=[tex] \frac{\frac{2}{3}+ \sqrt{2}}{2} [/tex]
=[tex] \frac{\frac{2}{3}+ \frac{3\sqrt{2}}{3} }{2} [/tex]
=[tex] \frac{{3\sqrt{2}}+2 }{6} [/tex]
let,
2/3 = a
√2 = b
rational number between a and b = (a+b)/2
=[tex] \frac{\frac{2}{3}+ \sqrt{2}}{2} [/tex]
=[tex] \frac{\frac{2}{3}+ \frac{3\sqrt{2}}{3} }{2} [/tex]
=[tex] \frac{{3\sqrt{2}}+2 }{6} [/tex]