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(1) Radio Ceylon broadcasts at 25m. Find the frequency of the station.
(2) A periodic longitudinal wave is sent on a slinky.The wave proceeds at the speed of 48m/s and each particle oscillates with the frequency of 12 Hz. Calculate the minimum separation between the positions, where the sliky is most compressed.

Answer :

kvnmurty
In a regular wave :  speed of the wave = Frequency * wavelength

1)   
     Frequency = c / wavelength = 3 * 10⁸ / 25 = 1.20 * 10⁷  Hertz

2)
   the minimum separation = wavelength = 48 m/s  /  12 Hz  =  4 meters.

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