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solve the linear equations x-2y=8 and 5x+3y=1 by algebraic method

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poojan
x-2y=8 is given
multiply it with 5
then it will be 5x-10y=40 --------------- 1
and 2nd equation is 5x+3y=1 ----------------2
by 1 and 2 we get
                           5x - 10y = 40
                        (-)5x + 3y=    1
                         -------------------------
                                13y = 39
                        ---------------------------
then y=39/13 = 3
       y = 3
by substituting it in 2
5x+3(3)=1
5x=1-9
5x=8
x=8/5

monalisa
x-2y=8 is given 
multiply it with 5 
then it will be 5x-10y=40..........(i)
and 2nd equation is 5x+3y=1.........(ii)
by equation (i)and(ii) we get
              3x-10y=40
              (-)5x+3y=1
  ...................................
         13y=39 
then y=39/13=3 
y=3
by subsiting it in 2 
5x+3(3)=1
5x=1-9
5x=8
x=8/5

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