Answer :
parallel sides = 19 and 13 cm
area = 128 cm^2
height = ?
area of trapezium = [tex] \frac{1}{2} * (sum of parallel sides) * height[/tex]
128 cm^2 = [tex] \frac{1}{2} * 32 * h [/tex]
128 / 32 = [tex] \frac{1}{2} * h[/tex]
[tex] \frac{2*4}{1} = h[/tex]
therefore h = 8 cm
area = 128 cm^2
height = ?
area of trapezium = [tex] \frac{1}{2} * (sum of parallel sides) * height[/tex]
128 cm^2 = [tex] \frac{1}{2} * 32 * h [/tex]
128 / 32 = [tex] \frac{1}{2} * h[/tex]
[tex] \frac{2*4}{1} = h[/tex]
therefore h = 8 cm
so formula for area of trapezium(A) = [tex] \frac{1}{2} [/tex] x sum of parallel sides(S) x perpendicular distance between parallel sides (P)
so here S = 19 + 13 cm = 32 cm
A = 128 cm²
P = ?
so 128 = [tex] \frac{1}{2} [/tex] x 32 x P
⇒ P = [tex] \frac{128*2}{32} [/tex]
⇒ P = 8 cm ANSWER
so here S = 19 + 13 cm = 32 cm
A = 128 cm²
P = ?
so 128 = [tex] \frac{1}{2} [/tex] x 32 x P
⇒ P = [tex] \frac{128*2}{32} [/tex]
⇒ P = 8 cm ANSWER