Answer :
parallel sides of trapezium = 3 : 4
height = 12 cm
area = 630 cm^2
let parallel sides of trapezium = 3x and 4x
area of trapezium = [tex] \frac{1}{2} (sum of parallel sides ) height[/tex]
630 cm^2 = [tex] \frac{1}{2} * 7x * 12[/tex]
x = 630 / 42
= 15
parallel sides are = 4 * 15 = 60 cm
3 * 15 = 45 cm
height = 12 cm
area = 630 cm^2
let parallel sides of trapezium = 3x and 4x
area of trapezium = [tex] \frac{1}{2} (sum of parallel sides ) height[/tex]
630 cm^2 = [tex] \frac{1}{2} * 7x * 12[/tex]
x = 630 / 42
= 15
parallel sides are = 4 * 15 = 60 cm
3 * 15 = 45 cm
so formula for area of trapezium(A) = x sum of parallel sides(S) x perpendicular distance between parallel sides (P)
so here S = 4x + 3x cm = 7x cm
A = 630 cm²
P = 12 cm
so 630 = x 7x x 12
⇒ x = [tex] \frac{630*2}{7*12} [/tex]
⇒ 3x = 45 cm ANSWER
so here S = 4x + 3x cm = 7x cm
A = 630 cm²
P = 12 cm
so 630 = x 7x x 12
⇒ x = [tex] \frac{630*2}{7*12} [/tex]
⇒ 3x = 45 cm ANSWER