Answered

The hydride ion H- is stronger base than its hydroxide ion OH-. Which of the following reaction will occur if sodium hydride (NaH) is dissolved in water
1. H- + H2O -> no reaction
2. H-(aq) + H2O->H2O
3. H-(aq) + H2O-> OH- + H2

Answer :

3 will occur AS H2O IN [Aq] is in form of ion H+ AND OH- SO,[H-] + [H+] + [OH-] =H2+OH-


skyfall63

When sodium hydride (NaH) is dissolved in water, the following reaction occurs:

[tex]\mathrm{H}^{-}(\mathrm{aq})+\mathrm{H}_{2} \mathrm{O} \rightarrow \mathrm{OH}^{-}+\mathrm{H}_{2}[/tex]

Hence option (3) is the correct answer.

Hydride ions are stronger base which means they will react with water to form hydroxide ion and water.

Since, hydride ion is a "stronger base", it will take [tex]H^{+}[/tex] from water to forms [tex]H_{2}[/tex] whereas [tex]\mathrm{OH}^{-} \ ions[/tex] will remains in the solution. This is called as "Bronsted-Lowry acid-base" theory.

This theory states that an acid can give [tex]H^{+}[/tex] ions whereas a base can accept [tex]H^{+}[/tex] ions.

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