Answer :
given ,
pressure = force / area
F= 288 kgf
T.S.A = 0.88 there fore M.S.A = 0.08
p = 288/0.08
= 3600 kgfm/s
pressure = force / area
F= 288 kgf
T.S.A = 0.88 there fore M.S.A = 0.08
p = 288/0.08
= 3600 kgfm/s
Answer:
Explanation:
Correct Question :-
A cuboid has a dimension of 0.4 × 0.6 × 0.2 m and a weight of 288 kgf. what is the maximum pressure exerted by a cuboid ?
Answer :-
Solution :-
Given :-
We know that,
Pressure, P = Force(F)/Area(A)
F = 288 kgf
Minimum surface area,
A = 0.08 m²
Maximum pressure,
⇒ P = Force(F)/Area(A)
⇒ P = 288 kgf/0.08 m²
⇒ P = 3600 kgfm²
Hence, the maximum pressure exerted by a cuboid is 3600 kgfm².