Answer :
distance, s = 500m
acceleration, g = 10 m/s²
initial speed, u = 0
let the time taken for the stone to reach the pond = t₁
s = ut₁ + 1/2 gt₁²
⇒ 500 = 0 + (1/2)×10×t₁²
⇒ t₁² = (2×500)/10 = 1000/10 = 100
⇒ t₁ = √100 = 10s
let the time taken by sound to reach the top of tower = t₂
speed of sound = 340 m/s
t₂ = 500/340 = 1.47s
total time = t₁+t₂ = 10+1.47 = 11.47s
So the splash will be heard at the top after 11.47 seconds.
acceleration, g = 10 m/s²
initial speed, u = 0
let the time taken for the stone to reach the pond = t₁
s = ut₁ + 1/2 gt₁²
⇒ 500 = 0 + (1/2)×10×t₁²
⇒ t₁² = (2×500)/10 = 1000/10 = 100
⇒ t₁ = √100 = 10s
let the time taken by sound to reach the top of tower = t₂
speed of sound = 340 m/s
t₂ = 500/340 = 1.47s
total time = t₁+t₂ = 10+1.47 = 11.47s
So the splash will be heard at the top after 11.47 seconds.
S = 500 m = distance to travel - for the stone
g = 10 m/sec/sec, initial velocity of stone u = 0
equation of the dynamics of stone :
s = u t + 1/2 g t^2
500 = 0 + 1/2 * 10 * t^2
t = 10 sec
Immediately after touching the water, in a fraction of second, there is a sound wave produced on the surface of water - splashing of water.
time for sound to reach the top = distance to travel / speed =
500 meter / 340 m/sec = 25/17 sec
total time = 10 sec + 25/17 sec