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a) A ship sends out ultrasound that returns from the seabed and is detected after 3.42 s. If the speed of ultrasound through seawater is 1531 m/s, what is the distance of the seabed from the ship ?
b) A ship sends out ultrasound produced by transmitter that returns from the sea bed and detected after 3.42 s. If the speed of ultrasound waves through sea water is 1530 m/s, what is the distance of the sea bed from the ship?

Answer :

Chotubls
Distance of sea bed from ship = Speed of sound * time taken / 2
= 1531 * 3.42 / 2 = 2618 m
TPS
time taken (t)= 3.42s
speed of sound in water (v) = 1531 m/s
distance of sea bed from the ship is given as
d = [tex] \frac{v \times t}{2}= \frac{1531 \times 3.42}{2}=\boxed{2618m} [/tex]  

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