The area of square is 4 sq cm A rectangle has the same perimeter as the square . If the length of the rectangle is 9.3 cm, what is its breadth? Also find which has greater area?
Let x be the breadth of the rectangle. As area of square is 49 cm^2, its side is 7 cm. Perimeter of square = 28 cm. Perimeter of rectangle = 2(9.3 + x) = 28 cm Thus, x = 4.7 cm Are of rectangle = 4.7 * 9.3 = 43.71 cm^2 Thus, the square has greater area.
let area of square be x^2 and here x^2=49 x=+-7 since length can't be negative so a=7 and we know that perimeter of rectangle = perimeter as square(.given) length of rectangle =9.3(given) perimeter of square =4x (where x is the length of side) plugging in the values and perimeter of rectangle=2(l+b) where l is length and b is breadth we get 4x = 2( l + b ) plugging in the given values we get 4*7=2(9.3+b) 28=18.6+2b 28-18.6=2b 9.4/2=b b=4.7 area=l*b =4.7*9.3 4.7 * 9.3 = 43.71 hence 49>43.71 so square has more area
