Answer :


by comparing with equation
[tex]a x^{2} +bx+c=0[/tex]
for equation
[tex] x^{2} -10x+18=0,a=1,b=-10,c=18[/tex]
sub. a,b and c in the formula 
[tex]x= \frac{-b+ \sqrt{ b^{2}-4ac } }{2a}, \frac{-b- \sqrt{ b^{2}-4ac } }{2a} [/tex]
u can find that roots are [tex]5- \sqrt{7},5+ \sqrt{7} [/tex]
split the middle term
x2-4x-6x+18
x(x-4)-3(2x+6)
(x-3)(2x+6)

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