While a helicopter is descending vertically an aviation kit dropped from it. If the height of the helicopter when the kit is dropped is 590 m. Find how much time does the kit reach the ground, also find its final velocity before it touches the ground?

Answer :

when the kit is dropped the velocity of kit is zero with respect to helicopter and fall under gravity so acceleration is g = 9.8 m/s² ,
s = 590m
apply 
s = ut + at²/2
590 = 0 + 9.8*t²/2
590/9.8 = t²
120.41 = t²
t = 10.97 sec.
apply 
v = u + at
v = 0 + 9.8*10.97
v = 107.5 m/s
  

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