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a charge particle of mass 1 gram is suspended through a silk thread of length 40cm in a horizontal electric field 4*10^4 NC-1.if the particle stays at a distance of 224 cm from the wall.find the charge.

Answer :

manitkapoor2
three forces act on mass here
1. Tension in the thread (along the thread)
2. mg weight of the mass particle (downward)
3. Electric force F=QE due to horizontal field
Let the angle between thread and vertical be [tex] \alpha [/tex]  
Then use sine law
[tex]T= \frac{mg}{sin(90+ \alpha )}= \frac{QE}{sin(180- \alpha )} [/tex]
[tex]m=10^{-3} Kg[/tex]
[tex]QE=mg(tan( \alpha ))[/tex]
[tex]Q= \frac{mg(tan( \alpha ))}{E} [/tex]
the length of thread is 40 cm
But the distance from the vertical cannot be 224 cm please check ur question
any way this would help u

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