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ABCD is a rectangle and BD is one of its diagonals.if ar(abd)=8cm square,find ar(bcd).

Answer :

In triangle ABD and BCD BD=BD(diagonals) BC=AD(opp. sides of rectangle are equal) AB=DC(opp. sides of rectangle are equal) therefore triange ABD is congruent to triangle BCD Hence ar(ABD)=ar(BCD) Area of triangle BCD is 8 sq.cm HOPE MY ANS WOULD HELPED YOU HAVE A GREAT AND BLESSSED DAY.....

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