Answer :
Let the radius = r
height is 6 times the radius,
so height, h= 6r
Rate of painting = 60 paisa per cm² =Rs. 0.60 per cm²
total cost = Rs 237.60
Total surface area = [tex] \frac{237.60}{0.60} =396\ cm^2[/tex]
[tex]TSA=2 \pi r(r+h)\\ \\ \Rightarrow 396=2 \pi r(r+6r)\\ \\ \Rightarrow 396=14 \pi r^2\\ \\ \Rightarrow r^2= \frac{396}{14 \pi } = \frac{396 \times 7}{14 \times 22} =9\\ \\ \Rightarrow r= \sqrt{9}=3cm \\ \\h=6r=6 \times 3=18cm[/tex]
Height is 18cm and radius is 3cm.
height is 6 times the radius,
so height, h= 6r
Rate of painting = 60 paisa per cm² =Rs. 0.60 per cm²
total cost = Rs 237.60
Total surface area = [tex] \frac{237.60}{0.60} =396\ cm^2[/tex]
[tex]TSA=2 \pi r(r+h)\\ \\ \Rightarrow 396=2 \pi r(r+6r)\\ \\ \Rightarrow 396=14 \pi r^2\\ \\ \Rightarrow r^2= \frac{396}{14 \pi } = \frac{396 \times 7}{14 \times 22} =9\\ \\ \Rightarrow r= \sqrt{9}=3cm \\ \\h=6r=6 \times 3=18cm[/tex]
Height is 18cm and radius is 3cm.
let the radius = r
then the height = 6r
cost of painting= Rs 237.60
rate of painting = Rs0.60/cm²
outer surface area of cylinder = cost of painting/rate of painting
= 237.60/0.60
=396 cm²
2πrh = 396
2 x π x r x 6r = 396
12 x 22/7 x r² = 396
396 x 7
r² = ------------
12 x 22
r² = 9
r = 3
radius = r = 3
height = 6r = 6 x 3 = 18
then the height = 6r
cost of painting= Rs 237.60
rate of painting = Rs0.60/cm²
outer surface area of cylinder = cost of painting/rate of painting
= 237.60/0.60
=396 cm²
2πrh = 396
2 x π x r x 6r = 396
12 x 22/7 x r² = 396
396 x 7
r² = ------------
12 x 22
r² = 9
r = 3
radius = r = 3
height = 6r = 6 x 3 = 18