Answer :
1 mole of neon atoms contain 6.022×10²³ atoms
12.044×10²² atoms = [tex] \frac{12.044 \times 10^{22}}{6.022 \times 10^{23}}\ moles = 0.2\ moles [/tex]
12.044×10²² atoms = [tex] \frac{12.044 \times 10^{22}}{6.022 \times 10^{23}}\ moles = 0.2\ moles [/tex]
6.022 X 10∧23 atoms of neon atom = 1 mole
1 atom of neon =1/ 6.022 X 10∧23
12.044 X 10∧22 atoms of neon = [(1/6.022 X 10∧23) x 12.044 X 10∧22 ]moles
= 2 X 10∧-1
1 atom of neon =1/ 6.022 X 10∧23
12.044 X 10∧22 atoms of neon = [(1/6.022 X 10∧23) x 12.044 X 10∧22 ]moles
= 2 X 10∧-1