Answer :
IF COLLINEAR AR OF TRIANGLE IS 0
0=1/2[-5[P+2]+1[-3]+4[1-P]] 1ST SUM
0=1/2[-5P-10-3+4-4P] 0=8[-4-K]+3[K-1]+2{1+4]
0=1/2[-9P-9] 0=-32-8K+3K-3+2+8
0=-9P-9 0=-25-5K
0=-9[P+1] 0=-5[K+5]
P=-1 K=-5
0=1/2[-5[P+2]+1[-3]+4[1-P]] 1ST SUM
0=1/2[-5P-10-3+4-4P] 0=8[-4-K]+3[K-1]+2{1+4]
0=1/2[-9P-9] 0=-32-8K+3K-3+2+8
0=-9P-9 0=-25-5K
0=-9[P+1] 0=-5[K+5]
P=-1 K=-5