find the mass of a solid cone of silver metal having base diameter 14 cm and vertical height 51 cm. the density of silver is 10 g/cm^3

Answer :

d=14
r=7
h=51
volume=[tex] \frac{1}{3} \pi r ^{2} h[/tex]
=[tex] \frac{1}{3} *\frac{22 }{7} *49*51 =2618 /cm ^{3} [/tex]
density=p
m=mass
v=volume
M=PV
=2618*10=26180 g

given
diameter=14cm
height =51 cm
density=10g/cm^3
Radius of base=7 cm
Volume of cone =1/3 πr²h
2618 cm³
As density is given by=mass/volume⇒mass=volumexdensity=2618x10=26180 g


As density is given by= mass/volume⇒