Answered

a body of mass 1.5Kg is thrown vertically upwards with an initial velocity of 15m/s.What will be its potential energy at the end of 2seconds?

Answer :

TPS
u = 15 m/s
g = -10 m/s²
t = 2s
h = ut + 0.5at²
⇒ h = 15×2 + 0.5×(-10)×2²
⇒ h = 30 - 0.5×10×4
⇒ h = 30 - 20
⇒ h = 10m

PE = mgh = 1.5×10×10 = 150J
Utsavsterbon
h = ut + 1/2at²
 h = 15×2 + 0.5×(-10)×2²
= 30 - 0.5×10×4
= 10m

PE = 1.5×10×10 = 150J
PE=150J

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