Answer :
1200*{1+R/100}2 =1348.32
{1+R/100}2 =134832/120000=11236/10000
{1+R/100]2 ={106/100}2
1+R/100 =106/100
R =6%
May be or may not be. if this is correct , mark it as best
{1+R/100}2 =134832/120000=11236/10000
{1+R/100]2 ={106/100}2
1+R/100 =106/100
R =6%
May be or may not be. if this is correct , mark it as best
Given, P= Rs 1200
A=Rs1348.32
n=2 yrs
We know, A=[tex] P(1+ \frac{R}{100} )^n [/tex]
1348.32= [tex]1200( \frac{100+R}{100} )^2[/tex]
[tex] \frac{1348.32}{1200} = (\frac{100+R}{100} )^2[/tex]
1.1236=[tex](\frac{100+R}{100} )^2[/tex]
[tex] \sqrt{1.1236} = \frac{100+R}{100} [/tex]
[tex]1.06= \frac{100+R}{100} [/tex]
[tex]1.06(100)-100=R[/tex]
[tex]106-100=R=6[/tex]
R=6
Therefore, rate of interest= 6%
A=Rs1348.32
n=2 yrs
We know, A=[tex] P(1+ \frac{R}{100} )^n [/tex]
1348.32= [tex]1200( \frac{100+R}{100} )^2[/tex]
[tex] \frac{1348.32}{1200} = (\frac{100+R}{100} )^2[/tex]
1.1236=[tex](\frac{100+R}{100} )^2[/tex]
[tex] \sqrt{1.1236} = \frac{100+R}{100} [/tex]
[tex]1.06= \frac{100+R}{100} [/tex]
[tex]1.06(100)-100=R[/tex]
[tex]106-100=R=6[/tex]
R=6
Therefore, rate of interest= 6%