Answer :

limzy
1/(a+1)+1/(b+1)+1/(c+1)
=1/(log base x(yz) +1) + 1/( log base y(zx) +1 ) +1/(log base z(xy) +1)
=(log x/ log y+ log z + log x) + (log y/ log z + log x +log y ) + (log z / log x +log y + log z)
=logx +log y + log z / log x +log y +log z
=1
hence proved

bmohankumar
1/(a+1)+1/(b+1)+1/(c+1)
=1/(log base x(yz) +1) + 1/( log base y(zx) +1 ) +1/(log base z(xy) +1)
=(log x/ log y+ log z + log x) + (log y/ log z + log x +log y ) + (log z / log x +log y + log z)
=logx +log y + log z / log x +log y +log z
=1

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