Log a / b = log (a - b)
a/b = a - b
a = ab - b²
a (b-1) = b²
a = b²/(b-1)
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f(x) = Log [ (1-x)/(1+x) ]
f( (1-x)/(1+x) ) = Log [ {1 - (1-x)/(1+x)} / { 1 + (1-x)/(1+x) } ]
= Log [ 2x / 2 ]
= Log x
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[tex]x^{\frac{1}{3}}+y^{\frac{1}{3}}=-z^{\frac{1}{3}}\\\\cubing\\\\x+y+3(xy)^\frac{1}{3}(x^{\frac{1}{3}}+y^{\frac{1}{3}})=-z\\\\x+y+z=-3(xy)^\frac{1}{3}(-z)^{\frac{1}{3}}\\\\\frac{x+y+z}{3}=(xyz)^{\frac{1}{3}}\\\\answer=\frac{1}{3}Log(xyz)[/tex]