Answer :
see the diagram.
1.5 = 5.5 i2 + 8 (i1 + i2) + 3 i2 = 16.5 i2 + 8 i1 -- (1)
2.0 = 4.5 i1 + 8 (i1 + i2) + 3 i1 = 8 i2 + 15.5 i1 --- (2)
(1) * 4 => 6 = 66 i2 + 32 i1
(2) *3 => 6 = 24 i2 + 46.5 i1
subtract: 0 = 42 i2 - 14.5 i1
i1 = 42/14.5 * i2 = 2.897 i2
substitute it in (2), we get:
2.0 = 8 * i2 + 15.5 * 2.897 * i2
i2 = 0.0378 Amp
i1 = 0.1095 Amp
Potential difference across the third wire with 8 ohm resistance:
(i1 + i2) 8 volts = 1.178 volts.
1.5 = 5.5 i2 + 8 (i1 + i2) + 3 i2 = 16.5 i2 + 8 i1 -- (1)
2.0 = 4.5 i1 + 8 (i1 + i2) + 3 i1 = 8 i2 + 15.5 i1 --- (2)
(1) * 4 => 6 = 66 i2 + 32 i1
(2) *3 => 6 = 24 i2 + 46.5 i1
subtract: 0 = 42 i2 - 14.5 i1
i1 = 42/14.5 * i2 = 2.897 i2
substitute it in (2), we get:
2.0 = 8 * i2 + 15.5 * 2.897 * i2
i2 = 0.0378 Amp
i1 = 0.1095 Amp
Potential difference across the third wire with 8 ohm resistance:
(i1 + i2) 8 volts = 1.178 volts.
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