Answer :
Sin 45°=1/√2
cos 45°=1/√2
Sin 45 + cos 45=
1/√2+1/√2=
2/√2=
2√2/2=
√2
cos 45°=1/√2
Sin 45 + cos 45=
1/√2+1/√2=
2/√2=
2√2/2=
√2
Answer:
sin45°+cos45°=[tex]\sqrt{2}[/tex]
Explanation:
Value of sin45°+cos45°
______________________
we know that,
i ) sin 45° = cos 45° = [tex]\frac{1}{\sqrt{2}}[/tex]
______________________
= [tex]\frac{1}{\sqrt{2}}+\frac{1}{\sqrt{2}}[/tex]
= [tex]\frac{2}{\sqrt{2}}[/tex]
/* Rationalising the denominator, we get */
= [tex]\frac{\sqrt{2}\times \sqrt{2}}{\sqrt{2}}[/tex]
/*After cancellation,we get*/
= $\sqrt{2}$
Therefore,
sin45°+cos45°=[tex]\sqrt{2}[/tex]
••••