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THE ANGLE OF ELEVATION OF THE INACCESSIBLE PEAK OF A HILLOCK FROM ITS FOOT IS 45 DEGREE . AFTER APPROACHING 100m ALONG A SLOPE OF THE HILLOCK , THE ANGLE OF ELEVATION OF THE PEAK AS OBSERVED IS 60 DEGREE. FIND THE HEIGHT OF THE HILLOCK ..??( PLES HELP WITH DIAGRAM )    

Answer :

just consider the hillock to be a straight verical line. let its height be h and the distance of the observer from the foot of the line be x. therefore angle of elevation from this point is 45 degrees. hence tan(45) = h/x => h/x = 1 => h=x. 
Now when we move closer to the foot by 100 m the angle of elevation increases to 60 degrees. therefore
tan(60) = h/x-100
=> √3 = h/h-100
=> h*(√3 - 1) = 100√3
=> h = 50*(3+√3) = 50*4.732 = 236.6 m

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