Answer :
LET THE MASS OF OBJECT BE m AND HEIGHT BE h
GIVEN POTENTIAL ENERGY =200
m×g×h=200
m=[tex] \frac{200}{hg} [/tex]...........1
mow when it is raised to height h/4
then potential energy=m×g×h/4
=[tex] \frac{200}{hg} [/tex]x[tex] \frac{h}{4} [/tex]×g
=50
GIVEN POTENTIAL ENERGY =200
m×g×h=200
m=[tex] \frac{200}{hg} [/tex]...........1
mow when it is raised to height h/4
then potential energy=m×g×h/4
=[tex] \frac{200}{hg} [/tex]x[tex] \frac{h}{4} [/tex]×g
=50