Answer :

consider a projectile thrown with a velocity 'v' with an angle Ф with the horizontal .
horizontal motion is uniform motion
the distance travelled by the projectile in time ' t'
x= vcosФt
t= x/v cosФ  ........ 1
vertical motion is uniformly accelerated motion
distance travelled by the particle in vertical direction in time 't' is
using (s=ut+1/2at²)

  y=vsinФt - 1/2 gt²  ...........2

from 1 and 2

y= vsinФ× x/cosФ - 1/2 g x²/v²cos²Ф


y= x tanФ - 1/2 g x²/v²cos²Ф

yαx²

hence the projectile is parabolic in nature.
VaibhavSR

Answer:

trajectory of projectile is perabola

Explanation:

The trajectory of a projectile is a the  parabola. Projectile motion is a form of motion where an object moves in a bilaterally symmetrical, parabolic path. The path that the object follows is called its trajectory. Projectile motion only occurs when there is one force applied at the beginning on the trajectory, after which the only interference is from gravity.

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