Answer :
The smallest 3-digit multiple of 7 is 105 = 15*7
The largest 3-digit multiple of 7 is 994 = 142*7So there are 142-14 = 128
3-digit multiples of 7, ie 128 3-digit numbers that are divisible by 7.
The largest 3-digit multiple of 7 is 994 = 142*7So there are 142-14 = 128
3-digit multiples of 7, ie 128 3-digit numbers that are divisible by 7.
15 is the starting digit gives 3 digit number when we multiply by 7, 7*15 = 105
142 is the ending digit gives 3 digit number when we multiply by 7, 7*142 = 994
Therefore, the total number of digits that gives 3 digit number when we multiply by 7 is 142-15 = 127 and we have to add 1 to 127 because 15 is excluded when we subtract.
so, the answer is 128.
142 is the ending digit gives 3 digit number when we multiply by 7, 7*142 = 994
Therefore, the total number of digits that gives 3 digit number when we multiply by 7 is 142-15 = 127 and we have to add 1 to 127 because 15 is excluded when we subtract.
so, the answer is 128.