Answer :
I suppose your question is [tex]y = 6sin(x) log_{10} (x+e)[/tex]. Then convert [tex]log_{10}(x+e)[/tex] to [tex] \frac{log_{e}(x+e)}{log_{e}10} [/tex]. Use product rule, you get this [tex] \frac{dy}{dx} = \frac{6}{log_{e}10}(cos(x)log_{e}(x+e)+\frac{sin(x)}{x+e})[/tex]