Answer :

Answer:root5

Explanation:

Answer:

[tex]-6 - \sqrt{35}[/tex]

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Step-by-Step Explanation:

[tex]\frac{\sqrt{5} +\sqrt{7} }{\sqrt{5} -\sqrt{7} }[/tex]

[tex]\frac{(\sqrt{5} +\sqrt{7})(\sqrt{5} +\sqrt{7} ) }{(\sqrt{5} -\sqrt{7})(\sqrt{5} +\sqrt{7} ) }[/tex]

[tex]\frac{(\sqrt{5} +\sqrt{7})^2 }{(\sqrt{5} -\sqrt{7})(\sqrt{5} +\sqrt{7} ) }[/tex]

[tex]\frac{(\sqrt{5} +\sqrt{7})^2 }{(\sqrt{5})^2 -(\sqrt{7})^2 }[/tex]

[tex]\frac{(\sqrt{5} +\sqrt{7})^2 }{5 -7 }[/tex]

[tex]\frac{(\sqrt{5} +\sqrt{7})^2 }{-2}[/tex]

[tex]\frac{(\sqrt{5})^2 +(\sqrt{7})^2 + 2(\sqrt{5})(\sqrt{7}) }{-2}[/tex]

[tex]\frac{5 +7 + 2(\sqrt{5*7}) }{-2}[/tex]

[tex]\frac{12+ 2\sqrt{5*7} }{-2}[/tex]

[tex]\frac{12+ 2\sqrt{35} }{-2}[/tex]

[tex]-(\frac{12+ 2\sqrt{35} }{2} )[/tex]

[tex]-(\frac{12}{2} + \frac{2\sqrt{35} }{2} )[/tex]

[tex]-(6 + \sqrt{35} )[/tex]

[tex]-6 - \sqrt{35}[/tex]

That's the answer.

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