artri
Answered

An alloy of iron and nickel weight 50g. It contains 80% iron. How much iron should be added to the alloy so that percentage of iron is increased to 90?
(A) 50 g (B) 60 g (C) 30 g (D) 40 g

Answer :

Step-by-step explanation:

To solve this problem, we need to find out how much iron should be added to the alloy to increase the percentage of iron to 90%.

Given:

- Initial weight of the alloy = 50g

- Initial percentage of iron in the alloy = 80%

- Final percentage of iron required = 90%

Let's calculate the amount of iron in the initial alloy:

Amount of iron in the initial alloy = 80% of 50g = 0.8 * 50g = 40g

Let x be the amount of iron added to the alloy to achieve a 90% iron content.

The total weight of the alloy after adding iron will be 50g (initial alloy weight) + x (iron added).

Now, the new percentage of iron in the alloy will be:

(40g + x) / (50g + x) = 90%

Solving this equation:

(40 + x) / (50 + x) = 0.90

40 + x = 0.90 * (50 + x)

40 + x = 45 + 0.90x

0.10x = 5

x = 50g

Therefore, the amount of iron that should be added to the alloy to increase the percentage of iron to 90% is 50g, which is option (A).

Other Questions