Answer:
The flux on the loop is [tex]9.1 \times 10^{-11} \mathrm{Wb}[/tex]
Given data:
Circular loop radius, r = 0.3 cm = [tex]3 \times 10^{-3} \ m[/tex]
Bigger circular loop radius, R = 20 cm = 0.2 m
Distance, x = 15 cm = 0.15 m
Current flowing, I = 2.0 A
To find:
Flux = ?
Solution:
Apply the flux formula given below:
[tex]\mathrm{Flux}=\frac{\mu_{0} \mathrm{IR}^{2} \mathrm{r}^{2} \pi}{2\left(\mathrm{R}^{2}+\mathrm{x}^{2}\right)^{3 / 2}}[/tex]
[tex]=\frac{4 \pi \times 10^{-7} \times 2.0 \times 0.2^{2} \times\left(3 \times 10^{-3}\right)^{2} \times \pi}{2\left(0.2^{2}+0.15^{2}\right)^{3 / 2}}[/tex]
[tex]=\frac{2.8447 \times 10^{-12}}{0.03125}[/tex]
[tex]=91.03 \times 10^{-12}[/tex]
[tex]\Rightarrow \text { Flux }=9.1 \times 10^{-11} \ \mathrm{Wb}[/tex]
