If Abhishek travels at a speed of 25 km/hr in his car he reaches his office 4 minutes late.If he drives at a speed of 30 km/hr he reaches 10 minutes early.Find the distace between his office and his home.
let.....x be required distance. x/s=t........... now by 1 st condition... x/25=t+1/15...................................( 4 minutes=1/15 hours) and by second equation x/30=t-1/6 from above equations, x/25 -1/15=x/30 +1/6 so x=35 km ans is 35 km
Let distance be x km Time taken to reach office at 25kmph=(x/25)*60 minutes Time taken to reach office at 30kmph =(x/30)*60 minute As per question (x/25)*60-4=(x/30)*60 +10 ⇒ (60x-100)/25= 2x+10 ⇒ 60x -100 = 50x + 250 ⇒ 10x=350 x=35 km
