Answer :
Consider two consecutive numbers like 5 and 6
5+6=11=S
larger number is 6 and smaller is 5
their squares are 36 and 25
36-25=11=S
option is c
5+6=11=S
larger number is 6 and smaller is 5
their squares are 36 and 25
36-25=11=S
option is c
let the smaller number is Tn and larger number is Tn+1
given Tn + Tn+1 = s
numbers are consecutive hence Tn+1 - Tn = 1
Tn+1∧2 -Tn∧2 = (Tn+1 - Tn )(Tn+1 + Tn )
= 1*s
= s
hence (c) is correct
given Tn + Tn+1 = s
numbers are consecutive hence Tn+1 - Tn = 1
Tn+1∧2 -Tn∧2 = (Tn+1 - Tn )(Tn+1 + Tn )
= 1*s
= s
hence (c) is correct